Boundary Value Problems

Eigenvalues and Eigenfunctions

Most often in boundary value problems, you will be asked to find the eigenvalues and eigenfunctions given a function and boundary conditions.

Here is my method for solving

  1. Form the characteristic equation.
  2. Solve in terms of lambda. It will often, but not always, render a square root with lambda inside.
  3. Consider the possible values for $r$ and what values of $\lambda$ would render such values. For example, if the quadratic formula simplified to $1 \pm \sqrt{2-\lambda}$, then two distinct real solutions would occur when $\lambda<2$, repeated roots would occur at $\lambda=0$, and imaginary roots would occur at $\lambda > 2$.
  4. It is often helpful to replace $\lambda$ with some other variable to consider when it is greater or less than some value. For example, if we wanted to test when $\lambda<1$, we could use $\lambda = 1 - \omega^2$
  5. For each of the possible conditions of $\lambda$:
    1. Create the general solutions.
    2. Use the boundary conditions to solve for the coefficients, avoiding setting a coefficient to zero when possible. Trigonometric functions can be equal to zero by cleverly setting them equal to values like $\pi n$ for sine or $\frac{\pi}{2}+\pi n$ for cosine.
    3. Plug in the value of $\lambda$ (the eigenvalue) back in to get the eigenfunction.

---

~ Jakob Nacanaynay
(nack-uh-nigh-nigh)
he/him/his